8z^2-800=0

Solution for 8z^2-800=0 equation:

8z^2-800=0

a = 8; b = 0; c = -800;
Δ = b2-4ac
Δ = 02-4·8·(-800)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160}{2*8}=\frac{-160}{16}
=-10
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160}{2*8}=\frac{160}{16}
=10
$